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40 Qwen_Qwen2.5-1.5B-Instruct gsm8k_main(0) 39 Question: Dana can run at a rate of speed four times faster than she can walk, but she can skip at a rate of speed that is half as fast as she can run. If she can skip at 3 miles per hour, how many miles can she travel in six hours if she spends one-third of the time running and two-thirds of the time walking? Answer: <|im_start|>system You are Qwen, created by Alibaba Cloud. You are a helpful assistant.<|im_end|> <|im_start|>user Output format: end your response with \boxed{<answer>} where <answer> is the final answer. Question: Dana can run at a rate of speed four times faster than she can walk, but she can skip at a rate of speed that is half as fast as she can run. If she can skip at 3 miles per hour, how many miles can she travel in six hours if she spends one-third of the time running and two-thirds of the time walking? Answer:<|im_end|> <|im_start|>assistant 18 1 [18] [stop:-] To determine how many miles Dana can travel in six hours, we need to calculate the distances she covers while running and walking. First, let's find Dana's walking speed. We know that her skipping speed is half her running speed. Given that she can skip at 3 miles per hour, her running speed is: \[ \text{Running speed} = 2 \times \text{Skipping speed} = 2 \times 3 = 6 \text{ miles per hour} \] Next, we calculate her walking speed. Since her running speed is four times her walking speed, we have: \[ \text{Walking speed} = \frac{\text{Running speed}}{4} = \frac{6}{4} = 1.5 \text{ miles per hour} \] Now, we need to determine how much time Dana spends running and walking. She spends one-third of the time running and two-thirds of the time walking. Since the total time is six hours, the time spent running is: \[ \text{Time running} = \frac{1}{3} \times 6 = 2 \text{ hours} \] The time spent walking is: \[ \text{Time walking} = \frac{2}{3} \times 6 = 4 \text{ hours} \] Now, we calculate the distance Dana covers while running and walking. The distance covered while running is: \[ \text{Distance running} = \text{Running speed} \times \text{Time running} = 6 \times 2 = 12 \text{ miles} \] The distance covered while walking is: \[ \text{Distance walking} = \text{Walking speed} \times \text{Time walking} = 1.5 \times 4 = 6 \text{ miles} \] Finally, the total distance Dana can travel in six hours is the sum of the distances covered while running and walking: \[ \text{Total distance} = \text{Distance running} + \text{Distance walking} = 12 + 6 = 18 \text{ miles} \] Thus, the final answer is: \[ \boxed{18} \]
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